Integrand size = 21, antiderivative size = 87 \[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=-\frac {(b \cot (e+f x))^{1+n} \operatorname {Hypergeometric2F1}\left (\frac {1+n}{2},\frac {1}{2} (1-m+n),\frac {3+n}{2},\cos ^2(e+f x)\right ) (a \sin (e+f x))^m \sin ^2(e+f x)^{\frac {1}{2} (1-m+n)}}{b f (1+n)} \]
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Time = 0.11 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {2683, 2697} \[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=-\frac {(a \sin (e+f x))^m (b \cot (e+f x))^{n+1} \sin ^2(e+f x)^{\frac {1}{2} (-m+n+1)} \operatorname {Hypergeometric2F1}\left (\frac {n+1}{2},\frac {1}{2} (-m+n+1),\frac {n+3}{2},\cos ^2(e+f x)\right )}{b f (n+1)} \]
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Rule 2683
Rule 2697
Rubi steps \begin{align*} \text {integral}& = \left (\left (\frac {\csc (e+f x)}{a}\right )^m (a \sin (e+f x))^m\right ) \int (b \cot (e+f x))^n \left (\frac {\csc (e+f x)}{a}\right )^{-m} \, dx \\ & = -\frac {(b \cot (e+f x))^{1+n} \operatorname {Hypergeometric2F1}\left (\frac {1+n}{2},\frac {1}{2} (1-m+n),\frac {3+n}{2},\cos ^2(e+f x)\right ) (a \sin (e+f x))^m \sin ^2(e+f x)^{\frac {1}{2} (1-m+n)}}{b f (1+n)} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 5 in optimal.
Time = 2.69 (sec) , antiderivative size = 289, normalized size of antiderivative = 3.32 \[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\frac {(3+m-n) \operatorname {AppellF1}\left (\frac {1}{2} (1+m-n),-n,1+m,\frac {1}{2} (3+m-n),\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) (b \cot (e+f x))^n \sin (e+f x) (a \sin (e+f x))^m}{f (1+m-n) \left ((3+m-n) \operatorname {AppellF1}\left (\frac {1}{2} (1+m-n),-n,1+m,\frac {1}{2} (3+m-n),\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )-2 \left (n \operatorname {AppellF1}\left (\frac {1}{2} (3+m-n),1-n,1+m,\frac {1}{2} (5+m-n),\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )+(1+m) \operatorname {AppellF1}\left (\frac {1}{2} (3+m-n),-n,2+m,\frac {1}{2} (5+m-n),\tan ^2\left (\frac {1}{2} (e+f x)\right ),-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )\right ) \tan ^2\left (\frac {1}{2} (e+f x)\right )\right )} \]
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\[\int \left (b \cot \left (f x +e \right )\right )^{n} \left (a \sin \left (f x +e \right )\right )^{m}d x\]
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\[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\int { \left (b \cot \left (f x + e\right )\right )^{n} \left (a \sin \left (f x + e\right )\right )^{m} \,d x } \]
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\[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\int \left (a \sin {\left (e + f x \right )}\right )^{m} \left (b \cot {\left (e + f x \right )}\right )^{n}\, dx \]
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\[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\int { \left (b \cot \left (f x + e\right )\right )^{n} \left (a \sin \left (f x + e\right )\right )^{m} \,d x } \]
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\[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\int { \left (b \cot \left (f x + e\right )\right )^{n} \left (a \sin \left (f x + e\right )\right )^{m} \,d x } \]
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Timed out. \[ \int (b \cot (e+f x))^n (a \sin (e+f x))^m \, dx=\int {\left (b\,\mathrm {cot}\left (e+f\,x\right )\right )}^n\,{\left (a\,\sin \left (e+f\,x\right )\right )}^m \,d x \]
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